
Note: In this lesson, as in the preceding one, all vector quantities will be underlined.

Index 22.Reference Frames 22a.Starlight Aberration 22b. Relativity 22c. Flight (1) 22d. Flight (2) 23. Inertial Forces 23a. The Centrifugal Force 23b. LooptheLoop 24a.The Rotating Earth 24b. Rotating Frames The Sun S1. Sunlight & Earth S1A. Weather S1B. Global Climate 
We now come back to motion in a circle.
The Centrifugal ForceMotion in a circle is an accelerated motion. Therefore, if we study it in the rotating frame of reference, we can expect inertial forces to appearlike the ones discussed in the preceding section.Suppose a person sits on a bus, moving in a straight line with constant speed v. As before, the forces involved are the passenger's weight F_{1} and the reaction force of the seat F_{2}, and in the absence of acceleration, the two cancel:

Suddenly the bus makes a sharp turn, following part of a circle of radius r. If the passenger's body is to stay in the seat as before, an extra force must be added, to keep it from continuing in a straight line (its natural tendency). If r_{u} is a unit vector (unit vectors are defined in the preceding section) directed outwards from the center of rotation, along the radius r, the force F_{2} exerted by the seat must increase to provide the centripetal force
–(mv^{2}/r)r_{u} that makes the passenger follow the motion of the bus:
The bus and the seat now constrain the passenger's body to follow part of a circle, and to do this must pull it towards the center. To stay in place (that is, balance the above equation), F_{2} on it must be increased by an additional force in the direction of –r_{u}, towards the center of the curve. How does this same event look in the frame of the bus? Adding (mv^{2}/r)r_{u} to both sides of the equation gives, in a similar way to what was done before
Equilibrium is attained and the passenger stays in place, if the equation above is satisfied. This can be viewed as the equilibrium between 3 forces F_{1}, F_{2} and the centrifugal force (mv^{2}/r)r_{u} directed along r_{u}, radially outwards. This can easily be generalized to any frame of reference moving around a circle: 
Equilibrium exists in the rotating frame if all forces balance, including an inertial "centrifugal" force (mv^{2}/r)r_{u}.

ExamplesWhen calculating the motions of the oceans and the atmosphere, it is much easier to use reference points on the rotating Earth and add a centrifugal force to all equations. That is one reason why the observed acceleration g due to gravity departs from the average value of 9.81: at the equator, the centrifugal force must be subtracted from the force of gravity, while at the pole no centrifugal force exists. Observations of g give values from 9.78 at the equators to 9.83 at the poles, but the centrifugal force is responsible for only part of that difference. The rest arises because the Earth is not a perfect sphere: the centrifugal force of its rotation causes its equator to bulge out, making the surface there more distant from the Earth´s center and thus weakening the gravitational pull.

Another example is the "loop the loop" feature found on some roller coasters in amusement parks. There the track descends on a long slope and then, at the bottom, turns in a complete circle (drawing) before leveling out again. At the point marked "A" the riders are briefly turned upside down, but no one ever falls out. How come? And (in the absence of friction), what is the minimum height h of the starting point S above A needed to ensure that the car passes safely through A? This is easily solved in the frame of the moving rollercoaster car. In that frame, the forces on the car at the top of the loop are

The car will just barely manage to get past point A if gravity and the centrifugal force are exactly equal, so that the rails need to exert no extra force:
The two vectors are both along r_{u} (with signs giving the direction), so everyhing reduces to an equation between ordinary numbers:
Suppose now the car has come down from a height h above the highest point in the loop. It has

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Substituting Divide by mg, add +1 to both sides:

The car must have started at least half a loop radius above A. Click here for an optional section handling the same problem by using the centripetal force. Questions from Users: *** Is the Centrifugal Force "Real"? Exploring FurtherAbout a classroom demonstration of "loop the loop" with a "hot wheels" toy carclick here. The roller coaster with the biggest loop is "Moonsault Scramble" in Japan, pictured at the beginning of this page.
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